Example 2.   Let  [Graphics:Images/RiemannSumMod_gr_34.gif]  over  [Graphics:Images/RiemannSumMod_gr_35.gif].  Use the right Riemann sum  with  n = 25, 50, and 100  to approximate the value of the integral.

Solution 2.

[Graphics:../Images/RiemannSumMod_gr_36.gif]

[Graphics:../Images/RiemannSumMod_gr_37.gif]

[Graphics:../Images/RiemannSumMod_gr_38.gif]
[Graphics:../Images/RiemannSumMod_gr_39.gif]
[Graphics:../Images/RiemannSumMod_gr_40.gif]



[Graphics:../Images/RiemannSumMod_gr_41.gif]

[Graphics:../Images/RiemannSumMod_gr_42.gif]

[Graphics:../Images/RiemannSumMod_gr_43.gif]
[Graphics:../Images/RiemannSumMod_gr_44.gif]
[Graphics:../Images/RiemannSumMod_gr_45.gif]



[Graphics:../Images/RiemannSumMod_gr_46.gif]

[Graphics:../Images/RiemannSumMod_gr_47.gif]

[Graphics:../Images/RiemannSumMod_gr_48.gif]
[Graphics:../Images/RiemannSumMod_gr_49.gif]
[Graphics:../Images/RiemannSumMod_gr_50.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) John H. Mathews 2004