Example 1. Consider
the function
.
1 (c). Find the terms
up to
in
the Maclaurin series and see how close it
approximates f[x].
Solution 1 (c).
1 (c). Find the
terms up to
in
the Maclaurin series and see how close it
approximates f[x].
Go ahead "enjoy" and add terms in the series up to
,
then plot the functions over the interval [-0.8, 0.8].
![[Graphics:../Images/TaylorPolyMod_gr_90.gif]](../Images/TaylorPolyMod_gr_90.gif)
Aside. Mathematica actually computes the higher derivatives of f[x] when calculating the Taylor series. Suppose you had to find the formula for the first 10 derivatives of f[x]. Could "you" do it ? Would you want to do it ?
Aside. The
function
is
"infinitely differentiable", that is it has a derivatives of all
orders. And the graph looks really smooth and nice for
"all x."
![[Graphics:../Images/TaylorPolyMod_gr_96.gif]](../Images/TaylorPolyMod_gr_96.gif)
So, why is the Maclaurin series severely restricted to the interval (-1,1). The answer lies in the study of complex numbers, we must look at the denominator and see where it vanishes.
The values
are
called singularities of f[x] and the
radius of convergence is the distance from the origin to the closest
one. But this topic must be left to another course called
"complex analysis" which is offered each spring. All
computer algebra systems such as Mathematica or Maple or
Derive do there underlying computations using complex
numbers. It is the mathematicians way to do it, and it is
really fun to work with complex functions.
(c) John H. Mathews 2004